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What is the axis of symmetry for the parabola given by the equation y = -2x^2 +
What is the axis of symmetry for the parabola given by the equation y = -2x^2 + 4x + 1?
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Q1
What is the axis of symmetry for the parabola given by the equation y = -2x^2 + 4x + 1?
x = 1
y = 1
x = 2
y = 2
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The axis of symmetry for a parabola in the form y = ax^2 + bx + c is given by x = -b/(2a). Here, a = -2, b = 4, so x = -4/(2*-2) = 1.
Questions & Step-by-step Solutions
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Q
Q: What is the axis of symmetry for the parabola given by the equation y = -2x^2 + 4x + 1?
Solution:
The axis of symmetry for a parabola in the form y = ax^2 + bx + c is given by x = -b/(2a). Here, a = -2, b = 4, so x = -4/(2*-2) = 1.
Steps: 7
Show Steps
Step 1: Identify the coefficients a and b from the equation y = -2x^2 + 4x + 1. Here, a = -2 and b = 4.
Step 2: Use the formula for the axis of symmetry, which is x = -b/(2a).
Step 3: Substitute the values of a and b into the formula: x = -4/(2 * -2).
Step 4: Calculate the denominator: 2 * -2 = -4.
Step 5: Now substitute this back into the equation: x = -4 / -4.
Step 6: Simplify the fraction: x = 1.
Step 7: The axis of symmetry for the parabola is x = 1.
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