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For the parabola y^2 = 16x, what is the coordinates of the vertex?
For the parabola y^2 = 16x, what is the coordinates of the vertex?
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Practice Questions
1 question
Q1
For the parabola y^2 = 16x, what is the coordinates of the vertex?
(0, 0)
(4, 0)
(0, 4)
(0, -4)
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The vertex of the parabola y^2 = 4px is at (0, 0).
Questions & Step-by-step Solutions
1 item
Q
Q: For the parabola y^2 = 16x, what is the coordinates of the vertex?
Solution:
The vertex of the parabola y^2 = 4px is at (0, 0).
Steps: 5
Show Steps
Step 1: Identify the standard form of the parabola. The equation y^2 = 4px is the standard form for a parabola that opens to the right.
Step 2: Compare the given equation y^2 = 16x with the standard form y^2 = 4px. Here, 4p = 16.
Step 3: Solve for p by dividing both sides of 4p = 16 by 4. This gives p = 4.
Step 4: The vertex of the parabola in the form y^2 = 4px is always at the point (0, 0).
Step 5: Therefore, the coordinates of the vertex for the parabola y^2 = 16x are (0, 0).
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