The pair of lines represented by the equation 2x^2 - 3xy + y^2 = 0 has slopes m1

Practice Questions

Q1
The pair of lines represented by the equation 2x^2 - 3xy + y^2 = 0 has slopes m1 and m2. What is the product m1*m2?
  1. -2
  2. 1
  3. 3/2
  4. 0

Questions & Step-by-Step Solutions

The pair of lines represented by the equation 2x^2 - 3xy + y^2 = 0 has slopes m1 and m2. What is the product m1*m2?
  • Step 1: Identify the given equation, which is 2x^2 - 3xy + y^2 = 0.
  • Step 2: Recognize that this equation represents a pair of lines.
  • Step 3: In a general quadratic equation of the form ax^2 + bxy + cy^2 = 0, the product of the slopes (m1 * m2) of the lines can be found using the formula m1 * m2 = c/a.
  • Step 4: Identify the coefficients from the equation: a = 2 (coefficient of x^2), b = -3 (coefficient of xy), and c = 1 (coefficient of y^2).
  • Step 5: Substitute the values of c and a into the formula: m1 * m2 = c/a = 1/2.
  • Step 6: Calculate the product: m1 * m2 = 1/2 = 0.5.
  • Step 7: Note that the product of the slopes is positive, indicating the lines are not perpendicular.
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