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The function f(x) = ln(x) + x has a minimum at:
The function f(x) = ln(x) + x has a minimum at:
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Practice Questions
1 question
Q1
The function f(x) = ln(x) + x has a minimum at:
x = 1
x = 0
x = e
x = 2
Show Solution
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Finding f'(x) = 1/x + 1. Setting f'(x) = 0 gives x = 1 as the minimum point.
Questions & Step-by-step Solutions
1 item
Q
Q: The function f(x) = ln(x) + x has a minimum at:
Solution:
Finding f'(x) = 1/x + 1. Setting f'(x) = 0 gives x = 1 as the minimum point.
Steps: 6
Show Steps
Step 1: Write down the function f(x) = ln(x) + x.
Step 2: Find the derivative of the function, f'(x). The derivative of ln(x) is 1/x and the derivative of x is 1, so f'(x) = 1/x + 1.
Step 3: Set the derivative equal to zero to find critical points: 1/x + 1 = 0.
Step 4: Solve for x. Rearranging gives 1/x = -1, which means x = -1. However, since ln(x) is only defined for x > 0, we ignore this solution.
Step 5: Check the behavior of f'(x) around x = 1. For x < 1, f'(x) is negative, and for x > 1, f'(x) is positive, indicating a minimum at x = 1.
Step 6: Conclude that the function f(x) has a minimum at x = 1.
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