If f(x) = x^4 - 8x^2 + 16, then the points of inflection are at:

Practice Questions

Q1
If f(x) = x^4 - 8x^2 + 16, then the points of inflection are at:
  1. x = 0
  2. x = ±2
  3. x = ±4
  4. x = 2

Questions & Step-by-Step Solutions

If f(x) = x^4 - 8x^2 + 16, then the points of inflection are at:
  • Step 1: Start with the function f(x) = x^4 - 8x^2 + 16.
  • Step 2: Find the first derivative f'(x) to determine the slope of the function.
  • Step 3: Calculate f'(x) = 4x^3 - 16x.
  • Step 4: Find the second derivative f''(x) to determine the concavity of the function.
  • Step 5: Calculate f''(x) = 12x^2 - 16.
  • Step 6: Set the second derivative equal to zero: 12x^2 - 16 = 0.
  • Step 7: Solve for x by adding 16 to both sides: 12x^2 = 16.
  • Step 8: Divide both sides by 12: x^2 = 16/12, which simplifies to x^2 = 4/3.
  • Step 9: Take the square root of both sides to find x: x = ±2.
  • Step 10: The points of inflection are at x = 2 and x = -2.
  • Second Derivative Test – Understanding how to find points of inflection by analyzing the second derivative of a function.
  • Critical Points – Identifying where the second derivative equals zero to find potential points of inflection.
  • Behavior of Functions – Recognizing how changes in concavity relate to the second derivative.
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