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The equation of the tangent to the curve y = x^2 at the point (2, 4) is:

Practice Questions

1 question
Q1
The equation of the tangent to the curve y = x^2 at the point (2, 4) is:
  1. y = 2x - 4
  2. y = 2x
  3. y = x + 2
  4. y = x^2 - 2

Questions & Step-by-step Solutions

1 item
Q
Q: The equation of the tangent to the curve y = x^2 at the point (2, 4) is:
Solution: The derivative f'(x) = 2x. At x = 2, f'(2) = 4. The equation of the tangent line is y - 4 = 4(x - 2), which simplifies to y = 2x - 4.
Steps: 0

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