The quadratic equation x^2 + 6x + 9 = 0 has roots that are:

Practice Questions

Q1
The quadratic equation x^2 + 6x + 9 = 0 has roots that are:
  1. Real and equal
  2. Real and distinct
  3. Complex
  4. None of these

Questions & Step-by-Step Solutions

The quadratic equation x^2 + 6x + 9 = 0 has roots that are:
  • Step 1: Identify the quadratic equation, which is in the form ax^2 + bx + c = 0. Here, a = 1, b = 6, and c = 9.
  • Step 2: Calculate the discriminant using the formula D = b^2 - 4ac. Substitute the values: D = 6^2 - 4(1)(9).
  • Step 3: Simplify the calculation: D = 36 - 36 = 0.
  • Step 4: Interpret the discriminant. Since D = 0, it means the quadratic equation has real and equal roots.
  • Step 5: Conclude that the roots of the equation x^2 + 6x + 9 = 0 are real and equal.
No concepts available.
Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely