In the expansion of (2x + 5)^4, what is the coefficient of x^2?

Practice Questions

Q1
In the expansion of (2x + 5)^4, what is the coefficient of x^2?
  1. 300
  2. 600
  3. 450
  4. 500

Questions & Step-by-Step Solutions

In the expansion of (2x + 5)^4, what is the coefficient of x^2?
  • Step 1: Identify the expression to expand, which is (2x + 5)^4.
  • Step 2: Recognize that we need to find the coefficient of x^2 in this expansion.
  • Step 3: Use the Binomial Theorem, which states that (a + b)^n = Σ [C(n, k) * a^(n-k) * b^k] for k = 0 to n.
  • Step 4: In our case, a = 2x, b = 5, and n = 4.
  • Step 5: We want the term where x has the power of 2, which means we need to find the term where (2x) is raised to the power of 2.
  • Step 6: This corresponds to k = 2 in the Binomial Theorem, since we want (2x)^(n-k) = (2x)^2.
  • Step 7: Calculate C(4, 2), which is the number of ways to choose 2 from 4. C(4, 2) = 4! / (2! * (4-2)!) = 6.
  • Step 8: Calculate (2)^2, which is 4.
  • Step 9: Calculate (5)^2, which is 25.
  • Step 10: Multiply these values together: Coefficient = C(4, 2) * (2)^2 * (5)^2 = 6 * 4 * 25.
  • Step 11: Perform the multiplication: 6 * 4 = 24, and then 24 * 25 = 600.
  • Step 12: Conclude that the coefficient of x^2 in the expansion of (2x + 5)^4 is 600.
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