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At what temperature does a reaction become spontaneous if ΔH = 50 kJ and ΔS = 0.
At what temperature does a reaction become spontaneous if ΔH = 50 kJ and ΔS = 0.1 kJ/K?
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Practice Questions
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Q1
At what temperature does a reaction become spontaneous if ΔH = 50 kJ and ΔS = 0.1 kJ/K?
500 K
250 K
1000 K
200 K
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Set ΔG = 0: 0 = ΔH - TΔS; T = ΔH/ΔS = 50 kJ / 0.1 kJ/K = 500 K.
Questions & Step-by-step Solutions
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Q
Q: At what temperature does a reaction become spontaneous if ΔH = 50 kJ and ΔS = 0.1 kJ/K?
Solution:
Set ΔG = 0: 0 = ΔH - TΔS; T = ΔH/ΔS = 50 kJ / 0.1 kJ/K = 500 K.
Steps: 7
Show Steps
Step 1: Understand the equation for spontaneity: ΔG = ΔH - TΔS.
Step 2: Recognize that a reaction becomes spontaneous when ΔG = 0.
Step 3: Set ΔG to 0 in the equation: 0 = ΔH - TΔS.
Step 4: Rearrange the equation to solve for T: T = ΔH / ΔS.
Step 5: Substitute the given values into the equation: T = 50 kJ / 0.1 kJ/K.
Step 6: Perform the division: 50 kJ divided by 0.1 kJ/K equals 500 K.
Step 7: Conclude that the temperature at which the reaction becomes spontaneous is 500 K.
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