Question: If 1 mole of a non-volatile solute is dissolved in 1 kg of water, what is the expected change in boiling point? (Kb for water = 0.512 °C kg/mol)
Options:
Correct Answer: 1.024 °C
Solution:
Boiling point elevation = i * Kb * m = 1 * 0.512 * 1 = 0.512 °C.