In the reaction 4Al + 3O2 → 2Al2O3, how many moles of Al2O3 are produced from 12 moles of Al?
Practice Questions
1 question
Q1
In the reaction 4Al + 3O2 → 2Al2O3, how many moles of Al2O3 are produced from 12 moles of Al?
2 moles
3 moles
6 moles
8 moles
According to the stoichiometry, 4 moles of Al produce 2 moles of Al2O3. Therefore, 12 moles of Al will produce (12/4) x 2 = 6 moles of Al2O3.
Questions & Step-by-step Solutions
1 item
Q
Q: In the reaction 4Al + 3O2 → 2Al2O3, how many moles of Al2O3 are produced from 12 moles of Al?
Solution: According to the stoichiometry, 4 moles of Al produce 2 moles of Al2O3. Therefore, 12 moles of Al will produce (12/4) x 2 = 6 moles of Al2O3.
Steps: 7
Step 1: Look at the chemical equation: 4Al + 3O2 → 2Al2O3.
Step 2: Identify the ratio of Al to Al2O3 from the equation. It shows that 4 moles of Al produce 2 moles of Al2O3.
Step 3: Determine how many moles of Al you have. In this case, you have 12 moles of Al.
Step 4: Use the ratio from Step 2 to find out how many moles of Al2O3 can be produced from 12 moles of Al.
Step 5: Set up the calculation: (12 moles of Al) / (4 moles of Al) = 3. This means you have 3 times the amount of Al compared to the 4 moles in the equation.
Step 6: Now multiply the result from Step 5 by the number of moles of Al2O3 produced per 4 moles of Al: 3 x 2 moles of Al2O3 = 6 moles of Al2O3.
Step 7: Conclude that from 12 moles of Al, you can produce 6 moles of Al2O3.