What is the standard enthalpy change for the reaction 2H2 + O2 → 2H2O if the ent

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Question: What is the standard enthalpy change for the reaction 2H2 + O2 → 2H2O if the enthalpy of formation of H2O is -285.8 kJ/mol?

Options:

Correct Answer: -571.6 kJ

Solution:

ΔH = 2 * (-285.8 kJ) = -571.6 kJ

What is the standard enthalpy change for the reaction 2H2 + O2 → 2H2O if the enthalpy of formation of H2O is -285.8 kJ/mol?

What is the standard enthalpy change for the reaction 2H2 + O2 → 2H2O if the enthalpy of formation of H2O is -285.8 kJ/mol?

Step 1: Identify the reaction: 2H2 + O2 → 2H2O.
Step 2: Understand that the enthalpy of formation of H2O is given as -285.8 kJ/mol.
Step 3: Since the reaction produces 2 moles of H2O, we need to calculate the total enthalpy change for 2 moles.
Step 4: Multiply the enthalpy of formation of H2O by the number of moles produced: 2 * (-285.8 kJ).
Step 5: Calculate the result: 2 * (-285.8 kJ) = -571.6 kJ.
Step 6: Conclude that the standard enthalpy change for the reaction is -571.6 kJ.

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