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What is the common oxidation state of chromium in Cr2O7^2-?
What is the common oxidation state of chromium in Cr2O7^2-?
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Q1
What is the common oxidation state of chromium in Cr2O7^2-?
+2
+3
+6
+7
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In Cr2O7^2-, chromium has a common oxidation state of +6.
Questions & Step-by-step Solutions
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Q
Q: What is the common oxidation state of chromium in Cr2O7^2-?
Solution:
In Cr2O7^2-, chromium has a common oxidation state of +6.
Steps: 9
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Step 1: Identify the compound Cr2O7^2-. This is called dichromate.
Step 2: Note that the overall charge of the dichromate ion is -2.
Step 3: Recognize that oxygen typically has an oxidation state of -2.
Step 4: Since there are 7 oxygen atoms, calculate the total oxidation state contributed by oxygen: 7 * (-2) = -14.
Step 5: Let the oxidation state of chromium be x. There are 2 chromium atoms, so their total contribution is 2x.
Step 6: Set up the equation for the total charge: 2x + (-14) = -2.
Step 7: Solve the equation: 2x - 14 = -2. Add 14 to both sides: 2x = 12.
Step 8: Divide by 2 to find x: x = 6.
Step 9: Conclude that the common oxidation state of chromium in Cr2O7^2- is +6.
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