What is the common oxidation state of chromium in Cr2O7^2-?

₹0.0

Question: What is the common oxidation state of chromium in Cr2O7^2-?

Options:

Correct Answer: +6

Solution:

In Cr2O7^2-, chromium has a common oxidation state of +6.

What is the common oxidation state of chromium in Cr2O7^2-?

What is the common oxidation state of chromium in Cr2O7^2-?

Step 1: Identify the compound Cr2O7^2-. This is called dichromate.
Step 2: Note that the overall charge of the dichromate ion is -2.
Step 3: Recognize that oxygen typically has an oxidation state of -2.
Step 4: Since there are 7 oxygen atoms, calculate the total oxidation state contributed by oxygen: 7 * (-2) = -14.
Step 5: Let the oxidation state of chromium be x. There are 2 chromium atoms, so their total contribution is 2x.
Step 6: Set up the equation for the total charge: 2x + (-14) = -2.
Step 7: Solve the equation: 2x - 14 = -2. Add 14 to both sides: 2x = 12.
Step 8: Divide by 2 to find x: x = 6.
Step 9: Conclude that the common oxidation state of chromium in Cr2O7^2- is +6.

No concepts available.