If the coefficient of consolidation (Cv) is 0.01 m²/year, what is the time requi

If the coefficient of consolidation (Cv) is 0.01 m²/year, what is the time required for 50% consolidation in a clay layer 5 m thick?

If the coefficient of consolidation (Cv) is 0.01 m²/year, what is the time required for 50% consolidation in a clay layer 5 m thick?

Step 1: Identify the given values. We have the coefficient of consolidation (Cv) = 0.01 m²/year and the thickness of the clay layer (H) = 5 m.
Step 2: Write down the formula for time required for consolidation: t = H² / Cv.
Step 3: Substitute the values into the formula. We have H = 5 m and Cv = 0.01 m²/year.
Step 4: Calculate H². H² = 5 m * 5 m = 25 m².
Step 5: Now, substitute H² into the formula: t = 25 m² / 0.01 m²/year.
Step 6: Perform the division: t = 25 / 0.01 = 2500 years.
Step 7: Since we want the time for 50% consolidation, we need to use a factor of 0.1. So, we calculate 2500 years * 0.1.
Step 8: Calculate the final time: 2500 years * 0.1 = 250 years.
Step 9: However, for 50% consolidation, we typically use a factor of 0.1, leading to approximately 1 year.

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