If a foundation has a width of 2 m and is subjected to a load of 400 kN, what is

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Question: If a foundation has a width of 2 m and is subjected to a load of 400 kN, what is the bearing pressure?

Options:

Correct Answer: 200 kPa

Solution:

Bearing pressure (q) is calculated as q = Load / Area. The area of the foundation is 2 m * 1 m = 2 m². Therefore, q = 400 kN / 2 m² = 200 kPa.

If a foundation has a width of 2 m and is subjected to a load of 400 kN, what is the bearing pressure?

If a foundation has a width of 2 m and is subjected to a load of 400 kN, what is the bearing pressure?

Step 1: Identify the load applied to the foundation, which is 400 kN.
Step 2: Identify the width of the foundation, which is 2 m.
Step 3: Assume the length of the foundation is 1 m (since it's not given, we can use this for calculation).
Step 4: Calculate the area of the foundation using the formula: Area = Width * Length. So, Area = 2 m * 1 m = 2 m².
Step 5: Use the formula for bearing pressure: q = Load / Area. Here, q = 400 kN / 2 m².
Step 6: Perform the calculation: 400 kN / 2 m² = 200 kPa.
Step 7: Conclude that the bearing pressure is 200 kPa.

Bearing Pressure Calculation – This concept involves calculating the pressure exerted by a load on a foundation based on its area.
Area Calculation – Understanding how to calculate the area of a foundation based on its dimensions is crucial for determining bearing pressure.