What is the standard enthalpy change for the reaction: 2H2(g) + O2(g) → 2H2O(g)

What is the standard enthalpy change for the reaction: 2H2(g) + O2(g) → 2H2O(g) if the enthalpy of formation of H2O(g) is -241.8 kJ/mol?

What is the standard enthalpy change for the reaction: 2H2(g) + O2(g) → 2H2O(g) if the enthalpy of formation of H2O(g) is -241.8 kJ/mol?

Step 1: Identify the reaction: 2H2(g) + O2(g) → 2H2O(g).
Step 2: Understand that the enthalpy of formation of H2O(g) is given as -241.8 kJ/mol.
Step 3: Since the reaction produces 2 moles of H2O(g), we need to calculate the total enthalpy change for 2 moles.
Step 4: Multiply the enthalpy of formation of H2O(g) by the number of moles produced: 2 * (-241.8 kJ).
Step 5: Calculate the result: 2 * (-241.8 kJ) = -483.6 kJ.
Step 6: Conclude that the standard enthalpy change for the reaction is -483.6 kJ.

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