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What is the change in enthalpy (ΔH) for the reaction: H2(g) + 1/2 O2(g) → H2O(l)

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Question: What is the change in enthalpy (ΔH) for the reaction: H2(g) + 1/2 O2(g) → H2O(l) if the standard enthalpy of formation of H2O(l) is -285.83 kJ/mol?

Options:

  1. -285.83 kJ/mol
  2. 285.83 kJ/mol
  3. 0 kJ/mol
  4. 571.66 kJ/mol

Correct Answer: -285.83 kJ/mol

Solution: 

The change in enthalpy for the reaction is equal to the standard enthalpy of formation of H2O(l), which is -285.83 kJ/mol.

What is the change in enthalpy (ΔH) for the reaction: H2(g) + 1/2 O2(g) → H2O(l)

Practice Questions

Q1
What is the change in enthalpy (ΔH) for the reaction: H2(g) + 1/2 O2(g) → H2O(l) if the standard enthalpy of formation of H2O(l) is -285.83 kJ/mol?
  1. -285.83 kJ/mol
  2. 285.83 kJ/mol
  3. 0 kJ/mol
  4. 571.66 kJ/mol

Questions & Step-by-Step Solutions

What is the change in enthalpy (ΔH) for the reaction: H2(g) + 1/2 O2(g) → H2O(l) if the standard enthalpy of formation of H2O(l) is -285.83 kJ/mol?
  • Step 1: Identify the reaction given: H2(g) + 1/2 O2(g) → H2O(l).
  • Step 2: Understand that the standard enthalpy of formation (ΔHf) is the change in enthalpy when one mole of a compound is formed from its elements in their standard states.
  • Step 3: Note that the standard enthalpy of formation of H2O(l) is given as -285.83 kJ/mol.
  • Step 4: Recognize that the reaction provided is the formation of water from hydrogen and oxygen, which means the change in enthalpy (ΔH) for this reaction is equal to the standard enthalpy of formation of H2O(l).
  • Step 5: Conclude that the change in enthalpy (ΔH) for the reaction is -285.83 kJ/mol.
  • Enthalpy of Formation – The standard enthalpy change when one mole of a compound is formed from its elements in their standard states.
  • Reaction Enthalpy – The change in enthalpy (ΔH) for a chemical reaction can be determined using the standard enthalpy of formation values.
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