In a galvanic cell, if the anode reaction is Zn → Zn²⁺ + 2e⁻, what is the half-r

In a galvanic cell, if the anode reaction is Zn → Zn²⁺ + 2e⁻, what is the half-reaction at the cathode if Cu²⁺ is reduced?

In a galvanic cell, if the anode reaction is Zn → Zn²⁺ + 2e⁻, what is the half-reaction at the cathode if Cu²⁺ is reduced?

Step 1: Identify the anode reaction, which is Zn → Zn²⁺ + 2e⁻. This means zinc is losing electrons.
Step 2: Understand that in a galvanic cell, the cathode is where reduction occurs, meaning a substance gains electrons.
Step 3: Recognize that Cu²⁺ is the substance being reduced at the cathode.
Step 4: Write the reduction half-reaction for Cu²⁺. Since it gains 2 electrons, the reaction is Cu²⁺ + 2e⁻ → Cu.
Step 5: Confirm that the cathode reaction is correctly written as Cu²⁺ + 2e⁻ → Cu.

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