Question: In a reaction where the rate law is rate = k[A]^2[B], what is the overall order of the reaction?
Options:
1
2
3
4
Correct Answer: 4
Solution:
The overall order is the sum of the exponents in the rate law: 2 (from [A]^2) + 1 (from [B]) = 3.
In a reaction where the rate law is rate = k[A]^2[B], what is the overall order
Practice Questions
Q1
In a reaction where the rate law is rate = k[A]^2[B], what is the overall order of the reaction?
1
2
3
4
Questions & Step-by-Step Solutions
In a reaction where the rate law is rate = k[A]^2[B], what is the overall order of the reaction?
Step 1: Identify the rate law given in the question, which is rate = k[A]^2[B].
Step 2: Look at the exponents in the rate law. The exponent for [A] is 2, and the exponent for [B] is 1.
Step 3: Add the exponents together. So, 2 (from [A]^2) + 1 (from [B]) = 3.
Step 4: The overall order of the reaction is the total sum of the exponents, which is 3.
Rate Law – The rate law expresses the relationship between the rate of a chemical reaction and the concentration of its reactants, with exponents indicating the order with respect to each reactant.
Overall Order of Reaction – The overall order of a reaction is determined by summing the exponents of the concentration terms in the rate law.
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