If the concentration of a reactant is halved in a first-order reaction, what hap

If the concentration of a reactant is halved in a first-order reaction, what happens to the rate?

If the concentration of a reactant is halved in a first-order reaction, what happens to the rate?

Step 1: Understand that a first-order reaction means the rate depends on the concentration of one reactant.
Step 2: Know that if you change the concentration of the reactant, the rate will change in a specific way.
Step 3: If you halve the concentration of the reactant, you are reducing it to half of its original amount.
Step 4: Since the rate is directly proportional to the concentration, halving the concentration will also halve the rate of the reaction.
Step 5: Conclude that the new rate will be half of the original rate.

No concepts available.