Question: A 3 kg object is moving with a speed of 4 m/s. If a net work of 24 J is done on the object, what will be its final speed?
Options:
Correct Answer: 8 m/s
Solution:
Initial kinetic energy = 0.5 Γ m Γ v^2 = 0.5 Γ 3 kg Γ (4 m/s)^2 = 24 J. Final kinetic energy = Initial + Work done = 24 J + 24 J = 48 J. Final speed = β(2 Γ KE/m) = β(2 Γ 48 J / 3 kg) = 6.93 m/s.