A 2 kg object is dropped from a height of 5 m. What is the work done by gravity
Practice Questions
Q1
A 2 kg object is dropped from a height of 5 m. What is the work done by gravity on the object just before it hits the ground?
10 J
20 J
30 J
40 J
Questions & Step-by-Step Solutions
A 2 kg object is dropped from a height of 5 m. What is the work done by gravity on the object just before it hits the ground?
Step 1: Identify the mass of the object. In this case, the mass (m) is 2 kg.
Step 2: Identify the height from which the object is dropped. Here, the height (h) is 5 m.
Step 3: Identify the acceleration due to gravity (g). The standard value is approximately 9.8 m/s².
Step 4: Use the formula for work done by gravity, which is Work = m × g × h.
Step 5: Substitute the values into the formula: Work = 2 kg × 9.8 m/s² × 5 m.
Step 6: Calculate the result: 2 × 9.8 × 5 = 98 J.
Step 7: Conclude that the work done by gravity on the object just before it hits the ground is 98 Joules.
Work Done by Gravity – The work done by gravity on an object is calculated using the formula W = m × g × h, where W is work, m is mass, g is acceleration due to gravity, and h is height.
