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A 1 kg mass is attached to a spring and compressed by 0.2 m. If the spring const

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Question: A 1 kg mass is attached to a spring and compressed by 0.2 m. If the spring constant is 100 N/m, what is the potential energy stored in the spring?

Options:

  1. 2 J
  2. 4 J
  3. 6 J
  4. 8 J

Correct Answer: 4 J

Solution: 

Potential energy in a spring is given by PE = 0.5kx². Thus, PE = 0.5 * 100 * (0.2)² = 2 J.

A 1 kg mass is attached to a spring and compressed by 0.2 m. If the spring const

Practice Questions

Q1
A 1 kg mass is attached to a spring and compressed by 0.2 m. If the spring constant is 100 N/m, what is the potential energy stored in the spring?
  1. 2 J
  2. 4 J
  3. 6 J
  4. 8 J

Questions & Step-by-Step Solutions

A 1 kg mass is attached to a spring and compressed by 0.2 m. If the spring constant is 100 N/m, what is the potential energy stored in the spring?
  • Step 1: Identify the formula for potential energy stored in a spring, which is PE = 0.5 * k * x².
  • Step 2: Identify the values needed for the formula: the spring constant (k) is 100 N/m and the compression distance (x) is 0.2 m.
  • Step 3: Substitute the values into the formula: PE = 0.5 * 100 * (0.2)².
  • Step 4: Calculate (0.2)², which is 0.04.
  • Step 5: Multiply 100 by 0.04 to get 4.
  • Step 6: Multiply 4 by 0.5 to get 2.
  • Step 7: Conclude that the potential energy stored in the spring is 2 Joules.
  • Potential Energy in Springs – The potential energy stored in a spring is calculated using the formula PE = 0.5kx², where k is the spring constant and x is the displacement from the equilibrium position.
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