A force of 30 N is applied at an angle of 60 degrees to a lever arm of length 2

Practice Questions

Q1
A force of 30 N is applied at an angle of 60 degrees to a lever arm of length 2 m. What is the torque about the pivot?
  1. 15 Nm
  2. 30 Nm
  3. 60 Nm
  4. 52 Nm

Questions & Step-by-Step Solutions

A force of 30 N is applied at an angle of 60 degrees to a lever arm of length 2 m. What is the torque about the pivot?
  • Step 1: Identify the force applied. In this case, the force (F) is 30 N.
  • Step 2: Identify the length of the lever arm. Here, the length (r) is 2 m.
  • Step 3: Identify the angle at which the force is applied. The angle (θ) is 60 degrees.
  • Step 4: Use the formula for torque (τ): τ = F × r × sin(θ).
  • Step 5: Calculate sin(60 degrees). The value of sin(60 degrees) is √3/2.
  • Step 6: Substitute the values into the torque formula: τ = 30 N × 2 m × (√3/2).
  • Step 7: Simplify the calculation: τ = 30 × 2 × (√3/2) = 30√3 Nm.
  • Step 8: If needed, calculate the approximate value of 30√3 Nm. This is about 51.96 Nm.
  • Torque Calculation – Understanding how to calculate torque using the formula τ = F × r × sin(θ), where F is the force, r is the lever arm length, and θ is the angle between the force and the lever arm.
  • Trigonometric Functions – Applying the sine function to find the effective component of the force that contributes to torque.
  • Units of Measurement – Recognizing that torque is measured in Newton-meters (Nm) and ensuring unit consistency in calculations.
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