If the moment of inertia of a body is 10 kg·m² and it is subjected to a torque o
Practice Questions
Q1
If the moment of inertia of a body is 10 kg·m² and it is subjected to a torque of 20 N·m, what is the angular acceleration?
2 rad/s²
0.5 rad/s²
5 rad/s²
10 rad/s²
Questions & Step-by-Step Solutions
If the moment of inertia of a body is 10 kg·m² and it is subjected to a torque of 20 N·m, what is the angular acceleration?
Step 1: Identify the given values. The moment of inertia (I) is 10 kg·m² and the torque (τ) is 20 N·m.
Step 2: Write down the formula that relates torque, moment of inertia, and angular acceleration. The formula is τ = Iα.
Step 3: Rearrange the formula to solve for angular acceleration (α). This gives us α = τ / I.
Step 4: Substitute the known values into the rearranged formula. This means we will calculate α = 20 N·m / 10 kg·m².
Step 5: Perform the division. Calculate 20 divided by 10, which equals 2.
Step 6: State the final result. The angular acceleration (α) is 2 rad/s².
Torque and Angular Acceleration – This question tests the understanding of the relationship between torque (τ), moment of inertia (I), and angular acceleration (α) as described by the equation τ = Iα.
