A light ray traveling in diamond (n=2.42) strikes the diamond-air interface. Wha

Practice Questions

Q1
A light ray traveling in diamond (n=2.42) strikes the diamond-air interface. What is the critical angle for total internal reflection?
  1. 24.4°
  2. 30.0°
  3. 36.0°
  4. 42.0°

Questions & Step-by-Step Solutions

A light ray traveling in diamond (n=2.42) strikes the diamond-air interface. What is the critical angle for total internal reflection?
  • Step 1: Understand that we are looking for the critical angle (θc) for light traveling from diamond to air.
  • Step 2: Recall that the refractive index of diamond (n1) is 2.42 and the refractive index of air (n2) is approximately 1.00.
  • Step 3: Use Snell's law, which states that sin(θc) = n2/n1.
  • Step 4: Substitute the values into the equation: sin(θc) = 1.00 / 2.42.
  • Step 5: Calculate the value: sin(θc) ≈ 0.4132.
  • Step 6: Use the inverse sine function (arcsin) to find θc: θc ≈ arcsin(0.4132).
  • Step 7: Calculate θc to find that it is approximately 24.4°.
  • Refraction and Total Internal Reflection – Understanding how light behaves at the interface between two media with different refractive indices, specifically the conditions for total internal reflection.
  • Snell's Law – Application of Snell's law to calculate angles of refraction and critical angles based on the refractive indices of the two media.
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