If the half-life of a first-order reaction is 10 minutes, what is the rate const

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Question: If the half-life of a first-order reaction is 10 minutes, what is the rate constant k?

Options:

Correct Answer: 0.0693 min^-1

Solution:

The rate constant k for a first-order reaction is given by k = 0.693/t1/2. Thus, k = 0.693/10 min = 0.0693 min^-1.

If the half-life of a first-order reaction is 10 minutes, what is the rate constant k?

If the half-life of a first-order reaction is 10 minutes, what is the rate constant k?

Step 1: Understand that the half-life (t1/2) of a first-order reaction is the time it takes for half of the reactant to be used up.
Step 2: Know the formula for the rate constant (k) of a first-order reaction, which is k = 0.693 / t1/2.
Step 3: Substitute the given half-life value (10 minutes) into the formula: k = 0.693 / 10 min.
Step 4: Perform the division: 0.693 divided by 10 equals 0.0693.
Step 5: Write the final answer with the correct units: k = 0.0693 min^-1.

First-Order Reaction Kinetics – Understanding the relationship between half-life and the rate constant for first-order reactions.
Half-Life Calculation – Applying the formula for half-life to determine the rate constant.