A projectile is launched with an initial speed of 50 m/s at an angle of 60 degre
Practice Questions
Q1
A projectile is launched with an initial speed of 50 m/s at an angle of 60 degrees. What is the horizontal component of its velocity?
25 m/s
50 m/s
43.3 m/s
30 m/s
Questions & Step-by-Step Solutions
A projectile is launched with an initial speed of 50 m/s at an angle of 60 degrees. What is the horizontal component of its velocity?
Step 1: Identify the initial speed of the projectile, which is given as 50 m/s.
Step 2: Identify the angle of launch, which is given as 60 degrees.
Step 3: Use the formula to find the horizontal component of velocity: v_x = u * cos(θ).
Step 4: Calculate cos(60 degrees). The value of cos(60 degrees) is 0.5.
Step 5: Substitute the values into the formula: v_x = 50 m/s * 0.5.
Step 6: Perform the multiplication: v_x = 25 m/s.
Projectile Motion – Understanding the components of velocity in projectile motion, specifically how to calculate the horizontal component using trigonometric functions.
Trigonometric Functions – Applying cosine to find the horizontal component of velocity based on the launch angle.
