For a reaction with an activation energy of 50 kJ/mol, what is the effect of inc
Practice Questions
Q1
For a reaction with an activation energy of 50 kJ/mol, what is the effect of increasing the temperature on the rate constant?
Rate constant decreases
Rate constant increases
Rate constant remains the same
Rate constant becomes zero
Questions & Step-by-Step Solutions
For a reaction with an activation energy of 50 kJ/mol, what is the effect of increasing the temperature on the rate constant?
Step 1: Understand that the activation energy (Ea) is the energy needed for a reaction to occur.
Step 2: Know that the rate constant (k) is a number that tells us how fast a reaction happens.
Step 3: Learn about the Arrhenius equation, which shows the relationship between temperature and the rate constant: k = A * e^(-Ea/(RT)).
Step 4: Recognize that 'A' is a constant, 'R' is the gas constant, and 'T' is the temperature in Kelvin.
Step 5: Realize that as temperature (T) increases, the value of -Ea/(RT) becomes less negative, which makes e^(-Ea/(RT)) larger.
Step 6: Conclude that a larger value of e^(-Ea/(RT)) means a larger rate constant (k), indicating that the reaction will happen faster.
Arrhenius Equation – The Arrhenius equation relates the rate constant of a reaction to the temperature and activation energy, indicating that higher temperatures increase the rate constant.
Activation Energy – Activation energy is the minimum energy required for a reaction to occur, and it influences how temperature changes affect reaction rates.
Temperature Effect on Reaction Rates – Increasing temperature generally increases the kinetic energy of molecules, leading to more frequent and effective collisions, thus increasing the rate constant.