If a circuit has a current of 5A flowing through a 10Ω resistor, what is the pow

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Question: If a circuit has a current of 5A flowing through a 10Ω resistor, what is the power dissipated by the resistor?

Options:

Correct Answer: 50W

Solution:

Power (P) = I^2 * R = 5^2 * 10 = 25 * 10 = 250W.

If a circuit has a current of 5A flowing through a 10Ω resistor, what is the power dissipated by the resistor?

If a circuit has a current of 5A flowing through a 10Ω resistor, what is the power dissipated by the resistor?

Step 1: Identify the current (I) flowing through the resistor. In this case, I = 5A.
Step 2: Identify the resistance (R) of the resistor. Here, R = 10Ω.
Step 3: Use the formula for power (P) dissipated by a resistor, which is P = I^2 * R.
Step 4: Substitute the values into the formula: P = (5A)^2 * 10Ω.
Step 5: Calculate (5A)^2, which is 25.
Step 6: Multiply 25 by 10Ω to find the power: 25 * 10 = 250W.
Step 7: Conclude that the power dissipated by the resistor is 250W.

Ohm's Law and Power Calculation – Understanding the relationship between current, resistance, and power in electrical circuits.