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In triangle ABC, if the lengths of the sides are 8, 15, and 17, what is the area
Practice Questions
Q1
In triangle ABC, if the lengths of the sides are 8, 15, and 17, what is the area of the triangle?
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Questions & Step-by-Step Solutions
In triangle ABC, if the lengths of the sides are 8, 15, and 17, what is the area of the triangle?
Steps
Concepts
Step 1: Identify the lengths of the sides of the triangle. Here, side a = 8, side b = 15, and side c = 17.
Step 2: Calculate the semi-perimeter (s) of the triangle using the formula s = (a + b + c) / 2. So, s = (8 + 15 + 17) / 2 = 20.
Step 3: Use Heron's formula to find the area of the triangle. The formula is Area = √[s(s-a)(s-b)(s-c)].
Step 4: Substitute the values into the formula. We have Area = √[20(20-8)(20-15)(20-17)].
Step 5: Calculate each term inside the square root: (20-8) = 12, (20-15) = 5, (20-17) = 3.
Step 6: Now substitute these values back into the formula: Area = √[20 * 12 * 5 * 3].
Step 7: Calculate the product: 20 * 12 = 240, then 240 * 5 = 1200, and finally 1200 * 3 = 3600.
Step 8: Take the square root of 3600 to find the area: √3600 = 60.
No concepts available.
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