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A student measures a length as 30.2 m, but the actual length is 30 m. What is th

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Question: A student measures a length as 30.2 m, but the actual length is 30 m. What is the error in measurement?

Options:

  1. 0.2 m
  2. 0.1 m
  3. 0.3 m
  4. 0.5 m

Correct Answer: 0.2 m

Solution: 

Error = Measured value - True value = 30.2 m - 30 m = 0.2 m.

A student measures a length as 30.2 m, but the actual length is 30 m. What is th

Practice Questions

Q1
A student measures a length as 30.2 m, but the actual length is 30 m. What is the error in measurement?
  1. 0.2 m
  2. 0.1 m
  3. 0.3 m
  4. 0.5 m

Questions & Step-by-Step Solutions

A student measures a length as 30.2 m, but the actual length is 30 m. What is the error in measurement?
  • Step 1: Identify the measured value. In this case, it is 30.2 m.
  • Step 2: Identify the true value. Here, it is 30 m.
  • Step 3: Use the formula for error in measurement: Error = Measured value - True value.
  • Step 4: Substitute the values into the formula: Error = 30.2 m - 30 m.
  • Step 5: Calculate the error: 30.2 m - 30 m = 0.2 m.
  • Measurement Error – Understanding the difference between a measured value and the true value to calculate error.
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