In a thermodynamic cycle, if the net work done by the system is 200 J and the he

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Question: In a thermodynamic cycle, if the net work done by the system is 200 J and the heat absorbed is 300 J, what is the change in internal energy?

Options:

100 J
200 J
300 J
500 J

Correct Answer: 100 J

Solution:

According to the First Law of Thermodynamics, ΔU = Q - W. Here, ΔU = 300 J - 200 J = 100 J.

In a thermodynamic cycle, if the net work done by the system is 200 J and the he

Practice Questions

In a thermodynamic cycle, if the net work done by the system is 200 J and the heat absorbed is 300 J, what is the change in internal energy?

100 J
200 J
300 J
500 J

Questions & Step-by-Step Solutions

In a thermodynamic cycle, if the net work done by the system is 200 J and the heat absorbed is 300 J, what is the change in internal energy?

Step 1: Understand the First Law of Thermodynamics, which states that the change in internal energy (ΔU) is equal to the heat absorbed (Q) minus the work done by the system (W).
Step 2: Identify the values given in the problem: heat absorbed (Q) is 300 J and net work done (W) is 200 J.
Step 3: Substitute the values into the formula: ΔU = Q - W.
Step 4: Calculate the change in internal energy: ΔU = 300 J - 200 J.
Step 5: Simplify the calculation: ΔU = 100 J.

First Law of Thermodynamics – The First Law states that the change in internal energy (ΔU) of a system is equal to the heat added to the system (Q) minus the work done by the system (W).

In a thermodynamic cycle, if the net work done by the system is 200 J and the he

What’s inside this PDF?

In a thermodynamic cycle, if the net work done by the system is 200 J and the he

Practice Questions

Questions & Step-by-Step Solutions

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