The lines represented by the equation 5x^2 - 6xy + 5y^2 = 0 intersect at:

Practice Questions

Q1
The lines represented by the equation 5x^2 - 6xy + 5y^2 = 0 intersect at:
  1. (0,0)
  2. (1,1)
  3. (2,2)
  4. (3,3)

Questions & Step-by-Step Solutions

The lines represented by the equation 5x^2 - 6xy + 5y^2 = 0 intersect at:
  • Step 1: Start with the equation 5x^2 - 6xy + 5y^2 = 0.
  • Step 2: Recognize that this is a quadratic equation in terms of x and y.
  • Step 3: Factor the equation to find the lines it represents.
  • Step 4: The equation can be factored as (5x - 5y)(x - y) = 0.
  • Step 5: Set each factor equal to zero: 5x - 5y = 0 and x - y = 0.
  • Step 6: Solve the first equation: 5x = 5y, which simplifies to x = y.
  • Step 7: Solve the second equation: x = y.
  • Step 8: Both equations give the same line, indicating they intersect along this line.
  • Step 9: To find the intersection point, substitute y = 0 into x = y, giving x = 0.
  • Step 10: Therefore, the lines intersect at the origin (0,0).
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