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What will happen to the equilibrium position of the reaction N2(g) + 3H2(g) β‡Œ 2N

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Question: What will happen to the equilibrium position of the reaction N2(g) + 3H2(g) β‡Œ 2NH3(g) when the pressure is increased?

Options:

  1. Shift to the left
  2. Shift to the right
  3. No change
  4. Depends on temperature

Correct Answer: Shift to the right

Solution:

Increasing pressure shifts the equilibrium towards the side with fewer moles of gas. Here, the right side has 2 moles (NH3) compared to 4 moles (N2 + 3H2), so the equilibrium shifts to the right.

What will happen to the equilibrium position of the reaction N2(g) + 3H2(g) β‡Œ 2N

Practice Questions

Q1
What will happen to the equilibrium position of the reaction N2(g) + 3H2(g) β‡Œ 2NH3(g) when the pressure is increased?
  1. Shift to the left
  2. Shift to the right
  3. No change
  4. Depends on temperature

Questions & Step-by-Step Solutions

What will happen to the equilibrium position of the reaction N2(g) + 3H2(g) β‡Œ 2NH3(g) when the pressure is increased?
  • Step 1: Identify the reaction: N2(g) + 3H2(g) β‡Œ 2NH3(g).
  • Step 2: Count the number of gas moles on each side of the reaction.
  • Step 3: On the left side (reactants), there are 1 mole of N2 and 3 moles of H2, totaling 4 moles.
  • Step 4: On the right side (products), there are 2 moles of NH3.
  • Step 5: Compare the total moles: 4 moles on the left vs. 2 moles on the right.
  • Step 6: Understand that increasing pressure favors the side with fewer moles of gas.
  • Step 7: Since the right side has fewer moles (2 moles), the equilibrium will shift to the right.
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