A light ray traveling in a medium with n=1.6 strikes the boundary with air at an

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Question: A light ray traveling in a medium with n=1.6 strikes the boundary with air at an angle of 50°. What will happen?

Options:

Correct Answer: Total internal reflection

Solution:

Calculate critical angle: θc = sin^(-1)(1/n) = sin^(-1)(1/1.6) ≈ 38.7°. Since 50° > 38.7°, total internal reflection occurs.

A light ray traveling in a medium with n=1.6 strikes the boundary with air at an angle of 50°. What will happen?

A light ray traveling in a medium with n=1.6 strikes the boundary with air at an angle of 50°. What will happen?

Step 1: Identify the refractive index of the medium. Here, n = 1.6.
Step 2: Determine the angle at which the light ray strikes the boundary. The angle is 50°.
Step 3: Calculate the critical angle (θc) using the formula θc = sin^(-1)(1/n).
Step 4: Substitute the value of n into the formula: θc = sin^(-1)(1/1.6).
Step 5: Calculate the critical angle: θc ≈ 38.7°.
Step 6: Compare the angle of incidence (50°) with the critical angle (38.7°).
Step 7: Since 50° is greater than 38.7°, total internal reflection occurs.

Refraction and Total Internal Reflection – Understanding how light behaves at the boundary between two different media, particularly when the angle of incidence exceeds the critical angle.