Question: If two waves of equal amplitude interfere, what is the maximum intensity observed?
Options:
A^2
2A^2
4A^2
A
Correct Answer: 2A^2
Solution:
Maximum intensity (I_max) = 4A^2 for two waves of equal amplitude A.
If two waves of equal amplitude interfere, what is the maximum intensity observe
Practice Questions
Q1
If two waves of equal amplitude interfere, what is the maximum intensity observed?
A^2
2A^2
4A^2
A
Questions & Step-by-Step Solutions
If two waves of equal amplitude interfere, what is the maximum intensity observed?
Step 1: Understand that two waves can interfere with each other, which means they can combine their effects.
Step 2: Know that the intensity of a wave is related to the square of its amplitude. If the amplitude of one wave is A, its intensity is proportional to A^2.
Step 3: Since we have two waves of equal amplitude A, the intensity of each wave is A^2.
Step 4: When two waves interfere constructively (which is the case for maximum intensity), their amplitudes add up. So, the total amplitude becomes A + A = 2A.
Step 5: Now, calculate the maximum intensity using the total amplitude. The intensity is proportional to the square of the total amplitude: (2A)^2.
Step 6: Simplify (2A)^2 to get 4A^2. This means the maximum intensity observed when two waves of equal amplitude interfere is 4A^2.
Wave Interference β The phenomenon where two or more waves superpose to form a resultant wave.
Intensity of Waves β The power per unit area carried by a wave, proportional to the square of its amplitude.
Constructive Interference β Occurs when waves combine to produce a wave of greater amplitude, leading to maximum intensity.
Soulshift FeedbackΓ
On a scale of 0β10, how likely are you to recommend
The Soulshift Academy?