Question: If the wavelength of light used in Young\'s experiment is 600 nm, what is the fringe width when the distance between the slits is 0.1 mm and the distance to the screen is 2 m?
Options:
Correct Answer: 0.06 mm
Solution:
Fringe width (β) = (λD)/d = (600 x 10^-9 * 2)/(0.1 x 10^-3) = 0.012 mm = 0.06 mm.