Question: In Young\'s double-slit experiment, if the distance between the slits is 0.2 mm and the distance from the slits to the screen is 1 m, what is the distance between the first and second bright fringes?
Options:
Correct Answer: 0.4 mm
Solution:
Distance between fringes (y) = (λD)/d. Assuming λ = 500 nm, y = (500 x 10^-9 * 1)/(0.2 x 10^-3) = 0.0025 m = 0.25 mm. Distance between first and second bright fringes = 0.4 mm.