What is the magnetic field due to a solenoid of length L, carrying n turns per u

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Question: What is the magnetic field due to a solenoid of length L, carrying n turns per unit length and current I?

Options:

Correct Answer: μ₀nI

Solution:

The magnetic field inside a long solenoid is B = μ₀nI.

What is the magnetic field due to a solenoid of length L, carrying n turns per unit length and current I?

What is the magnetic field due to a solenoid of length L, carrying n turns per unit length and current I?

Step 1: Understand what a solenoid is. A solenoid is a coil of wire that creates a magnetic field when an electric current passes through it.
Step 2: Identify the key components: length (L), number of turns per unit length (n), and current (I).
Step 3: Recognize that the magnetic field inside a long solenoid is uniform and can be calculated using a specific formula.
Step 4: The formula for the magnetic field (B) inside a long solenoid is B = μ₀nI, where μ₀ is the permeability of free space.
Step 5: Remember that 'n' is the number of turns of wire per unit length, and 'I' is the current flowing through the wire.

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