In how many ways can 3 different colored balls be chosen from a set of 7?

Practice Questions

Q1
In how many ways can 3 different colored balls be chosen from a set of 7?
  1. 35
  2. 21
  3. 42
  4. 56

Questions & Step-by-Step Solutions

In how many ways can 3 different colored balls be chosen from a set of 7?
  • Step 1: Understand that we have 7 different colored balls.
  • Step 2: We want to choose 3 balls from these 7.
  • Step 3: The formula to find the number of ways to choose 'r' items from 'n' items is C(n, r) = n! / (r! * (n - r)!).
  • Step 4: In our case, n = 7 (the total number of balls) and r = 3 (the number of balls we want to choose).
  • Step 5: Plug the values into the formula: C(7, 3) = 7! / (3! * (7 - 3)!).
  • Step 6: Simplify the formula: C(7, 3) = 7! / (3! * 4!).
  • Step 7: Calculate 7! (which is 7 x 6 x 5 x 4 x 3 x 2 x 1) and 3! (which is 3 x 2 x 1) and 4! (which is 4 x 3 x 2 x 1).
  • Step 8: Substitute the values: C(7, 3) = 5040 / (6 * 24).
  • Step 9: Calculate the denominator: 6 * 24 = 144.
  • Step 10: Now divide: 5040 / 144 = 35.
  • Step 11: Therefore, there are 35 different ways to choose 3 balls from 7.
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