For the equilibrium 2SO2(g) + O2(g) ⇌ 2SO3(g), what will happen if O2 is removed

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Question: For the equilibrium 2SO2(g) + O2(g) ⇌ 2SO3(g), what will happen if O2 is removed?

Options:

Correct Answer: Equilibrium shifts to the left

Solution:

Removing O2 will shift the equilibrium to the left to produce more O2, in accordance with Le Chatelier\'s Principle.

For the equilibrium 2SO2(g) + O2(g) ⇌ 2SO3(g), what will happen if O2 is removed?

For the equilibrium 2SO2(g) + O2(g) ⇌ 2SO3(g), what will happen if O2 is removed?

Step 1: Understand the equilibrium reaction: 2SO2(g) + O2(g) ⇌ 2SO3(g).
Step 2: Identify what happens when O2 is removed from the system.
Step 3: Recall Le Chatelier's Principle, which states that if a change is made to a system at equilibrium, the system will adjust to counteract that change.
Step 4: Since O2 is a reactant in the reaction, removing it will decrease its concentration.
Step 5: To counteract the decrease in O2, the equilibrium will shift to the left, meaning it will produce more O2.
Step 6: As a result, the reaction will favor the formation of the reactants (2SO2 and O2) over the products (2SO3).

Le Chatelier's Principle – When a system at equilibrium is subjected to a change in concentration, pressure, or temperature, the system will adjust to counteract that change and restore a new equilibrium.