A 2 kg block is sliding on a frictionless surface. If a force of 6 N is applied,
Practice Questions
Q1
A 2 kg block is sliding on a frictionless surface. If a force of 6 N is applied, what is its acceleration?
2 m/s²
3 m/s²
4 m/s²
6 m/s²
Questions & Step-by-Step Solutions
A 2 kg block is sliding on a frictionless surface. If a force of 6 N is applied, what is its acceleration?
Step 1: Identify the mass of the block, which is 2 kg.
Step 2: Identify the force applied to the block, which is 6 N.
Step 3: Use the formula for acceleration, which is a = F/m.
Step 4: Substitute the values into the formula: a = 6 N / 2 kg.
Step 5: Calculate the acceleration: 6 N divided by 2 kg equals 3 m/s².
Newton's Second Law of Motion – This law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
