A 6 kg object is at rest on a horizontal surface. If a horizontal force of 12 N

Practice Questions

Q1
A 6 kg object is at rest on a horizontal surface. If a horizontal force of 12 N is applied, what is the acceleration assuming no friction?
  1. 1 m/s²
  2. 2 m/s²
  3. 3 m/s²
  4. 4 m/s²

Questions & Step-by-Step Solutions

A 6 kg object is at rest on a horizontal surface. If a horizontal force of 12 N is applied, what is the acceleration assuming no friction?
  • Step 1: Identify the mass of the object. The mass is given as 6 kg.
  • Step 2: Identify the force applied to the object. The force is given as 12 N.
  • Step 3: Recall the formula for acceleration, which is F = ma, where F is force, m is mass, and a is acceleration.
  • Step 4: Rearrange the formula to solve for acceleration (a). This gives us a = F/m.
  • Step 5: Substitute the values into the formula. So, a = 12 N / 6 kg.
  • Step 6: Perform the division. 12 N divided by 6 kg equals 2 m/s².
  • Step 7: Conclude that the acceleration of the object is 2 m/s².
  • Newton's Second Law of Motion – This law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
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