A 12 kg box is pulled with a force of 60 N at an angle of 30 degrees to the hori

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Question: A 12 kg box is pulled with a force of 60 N at an angle of 30 degrees to the horizontal. What is the horizontal component of the force?

Options:

Correct Answer: 51.96 N

Solution:

The horizontal component is F_horizontal = F * cos(θ) = 60 N * cos(30°) = 60 N * (√3/2) = 51.96 N.

A 12 kg box is pulled with a force of 60 N at an angle of 30 degrees to the horizontal. What is the horizontal component of the force?

A 12 kg box is pulled with a force of 60 N at an angle of 30 degrees to the horizontal. What is the horizontal component of the force?

Step 1: Identify the total force being applied, which is 60 N.
Step 2: Identify the angle at which the force is applied, which is 30 degrees.
Step 3: Use the formula to find the horizontal component of the force: F_horizontal = F * cos(θ).
Step 4: Substitute the values into the formula: F_horizontal = 60 N * cos(30°).
Step 5: Calculate cos(30°), which is √3/2 or approximately 0.866.
Step 6: Multiply 60 N by cos(30°): F_horizontal = 60 N * (√3/2).
Step 7: Calculate the result: F_horizontal = 60 N * 0.866 = 51.96 N.

Force Components – Understanding how to resolve a force into its horizontal and vertical components using trigonometric functions.
Trigonometry in Physics – Applying cosine to find the horizontal component of a force when given an angle.