An object is projected at an angle of 60 degrees with an initial velocity of 30
Practice Questions
Q1
An object is projected at an angle of 60 degrees with an initial velocity of 30 m/s. What is the horizontal component of its velocity?
15 m/s
25 m/s
30 m/s
20 m/s
Questions & Step-by-Step Solutions
An object is projected at an angle of 60 degrees with an initial velocity of 30 m/s. What is the horizontal component of its velocity?
Step 1: Identify the initial velocity (u) of the object, which is given as 30 m/s.
Step 2: Identify the angle of projection (θ), which is given as 60 degrees.
Step 3: Use the formula to find the horizontal component of velocity (Vx): Vx = u * cos(θ).
Step 4: Calculate cos(60 degrees). The value of cos(60 degrees) is 0.5.
Step 5: Substitute the values into the formula: Vx = 30 m/s * 0.5.
Step 6: Perform the multiplication: Vx = 15 m/s.
Projectile Motion – Understanding the components of velocity in projectile motion, specifically how to calculate the horizontal component using trigonometric functions.
Trigonometric Functions – Applying cosine to find the horizontal component of velocity based on the angle of projection.
