What is the bond order of a molecule with 10 electrons in bonding orbitals and 4

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Question: What is the bond order of a molecule with 10 electrons in bonding orbitals and 4 electrons in antibonding orbitals?

Options:

Correct Answer: 2

Solution:

Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2 = (10 - 4) / 2 = 3.

What is the bond order of a molecule with 10 electrons in bonding orbitals and 4 electrons in antibonding orbitals?

What is the bond order of a molecule with 10 electrons in bonding orbitals and 4 electrons in antibonding orbitals?

Step 1: Identify the number of bonding electrons in the molecule. In this case, there are 10 bonding electrons.
Step 2: Identify the number of antibonding electrons in the molecule. Here, there are 4 antibonding electrons.
Step 3: Use the bond order formula: Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2.
Step 4: Substitute the values into the formula: Bond order = (10 - 4) / 2.
Step 5: Calculate the result: 10 - 4 equals 6, then divide 6 by 2 to get 3.
Step 6: Conclude that the bond order of the molecule is 3.

Bond Order Calculation – Bond order is calculated using the formula (Number of bonding electrons - Number of antibonding electrons) / 2, which indicates the stability and strength of a bond in a molecule.