If 1 liter of a 2 M solution is diluted to 3 liters, what is the new molarity?

₹0.0

Question: If 1 liter of a 2 M solution is diluted to 3 liters, what is the new molarity?

Options:

Correct Answer: 0.67 M

Solution:

Using the dilution formula M1V1 = M2V2, (2 M)(1 L) = M2(3 L) => M2 = 2/3 = 0.67 M.

If 1 liter of a 2 M solution is diluted to 3 liters, what is the new molarity?

If 1 liter of a 2 M solution is diluted to 3 liters, what is the new molarity?

Step 1: Identify the initial molarity (M1) and volume (V1) of the solution. Here, M1 = 2 M and V1 = 1 L.
Step 2: Identify the final volume (V2) after dilution. Here, V2 = 3 L.
Step 3: Use the dilution formula: M1 * V1 = M2 * V2.
Step 4: Substitute the known values into the formula: (2 M) * (1 L) = M2 * (3 L).
Step 5: Calculate the left side: 2 M * 1 L = 2 mol.
Step 6: Set up the equation: 2 mol = M2 * 3 L.
Step 7: Solve for M2 by dividing both sides by 3 L: M2 = 2 mol / 3 L.
Step 8: Calculate M2: M2 = 0.67 M.

Dilution of Solutions – Understanding how to calculate the new molarity after diluting a solution using the formula M1V1 = M2V2.