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What is the van 't Hoff factor (i) for a strong electrolyte that completely diss

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Question: What is the van \'t Hoff factor (i) for a strong electrolyte that completely dissociates into 3 ions?

Options:

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Correct Answer: 3

Solution: 

The van \'t Hoff factor (i) is equal to the number of particles the solute dissociates into. For a strong electrolyte that dissociates into 3 ions, i = 3.

What is the van 't Hoff factor (i) for a strong electrolyte that completely diss

Practice Questions

Q1
What is the van 't Hoff factor (i) for a strong electrolyte that completely dissociates into 3 ions?
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Questions & Step-by-Step Solutions

What is the van 't Hoff factor (i) for a strong electrolyte that completely dissociates into 3 ions?
  • Step 1: Understand what a strong electrolyte is. A strong electrolyte is a substance that completely dissociates into ions when dissolved in water.
  • Step 2: Identify how many ions the strong electrolyte dissociates into. In this case, it dissociates into 3 ions.
  • Step 3: Know that the van 't Hoff factor (i) represents the number of particles the solute breaks into when it dissolves.
  • Step 4: Since the strong electrolyte dissociates into 3 ions, the van 't Hoff factor (i) is equal to 3.
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