If 1 mole of a non-electrolyte solute is dissolved in 1 kg of water, what is the

Practice Questions

Q1
If 1 mole of a non-electrolyte solute is dissolved in 1 kg of water, what is the freezing point depression?
  1. 0 °C
  2. 1.86 °C
  3. 3.72 °C
  4. 5.58 °C

Questions & Step-by-Step Solutions

If 1 mole of a non-electrolyte solute is dissolved in 1 kg of water, what is the freezing point depression?
  • Step 1: Understand the formula for freezing point depression, which is ΔTf = i * Kf * m.
  • Step 2: Identify the values needed for the formula. For a non-electrolyte solute, the van 't Hoff factor (i) is 1.
  • Step 3: Find the value of Kf for water, which is 1.86 °C kg/mol.
  • Step 4: Determine the molality (m) of the solution. Since 1 mole of solute is dissolved in 1 kg of water, m = 1 mol/kg.
  • Step 5: Plug the values into the formula: ΔTf = 1 * 1.86 °C kg/mol * 1 mol/kg.
  • Step 6: Calculate the result: ΔTf = 1.86 °C.
  • Freezing Point Depression – The decrease in the freezing point of a solvent when a solute is added, calculated using the formula ΔTf = i * Kf * m.
  • Colligative Properties – Properties that depend on the number of solute particles in a solution, not their identity.
  • Non-Electrolyte Behavior – Non-electrolytes do not dissociate into ions in solution, hence the van 't Hoff factor (i) is 1.
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